(3x+1)(x+1)^2=96

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Solution for (3x+1)(x+1)^2=96 equation: 



(3x+1)(x+1)^2=96

We move all terms to the left:

(3x+1)(x+1)^2-(96)=0

We multiply parentheses ..

(+3x^2+3x+x+1)^2-96=0

We move all terms containing x to the left, all other terms to the right

(+3x^2+3x+x+1)^2=96

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